x^2+9x-38=0

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Solution for x^2+9x-38=0 equation:



x^2+9x-38=0
a = 1; b = 9; c = -38;
Δ = b2-4ac
Δ = 92-4·1·(-38)
Δ = 233
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{233}}{2*1}=\frac{-9-\sqrt{233}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{233}}{2*1}=\frac{-9+\sqrt{233}}{2} $

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